نتایج جستجو برای: a fraction 356 vs 255
تعداد نتایج: 13491427 فیلتر نتایج به سال:
Abstract We present measurements of the soft X-ray background emission for 130 Suzaku observations at 75° < l 285° and |b| > 15° obtained from 2005 to 2015, covering nearly one solar cycle. In addition standard model consisting local hot bubble Milky Way Halo (MWH), we include a collisional-ionization-equilibrium component with temperature ?0.8 keV reproduce spectra significant fr...
Milk yield and plasma oxytocin (OT), prolactin (PRL), and cortisol (CORT) during suckling and machine milking were measured in multiparous ewes subjected to a mixed management system of 3 sucklings and two daily milkings. Peak hormones were significantly increased and were similar during suckling and milking for PRL (181 vs. 163.3 ng x mL(-1)) and CORT (12.5 vs. 11.5 ng x mL(-1)). During the pe...
Automatic individual calibration in fall detection--an integrative ambulatory measurement framework.
The objective of the current study was to demonstrate the utility of a new integrative ambulatory measurement (IAM) framework by developing and evaluating an individual calibration function in fall detection application. Ten healthy elderly persons were involved in a laboratory study and tested in a protocol comprising various types of activities of daily living and slip-induced backward falls....
Cardiovascular magnetic resonance (CMR) has become a reference standard for the measurement of cardiac volumes, function, and mass. This study aims to reconstruct three dimensional modeling of the left ventricle (LV) in patients with heart failure (HF) using CMRtools and thereby derive the LV functional indices. CMR images were acquired in 41 subjects (6 females) with heart failure (HF) and 12 ...
Notes taken in Professor Boneh’s Introduction to Cryptography course (CS 255) in Winter, 2012. There may be errors! Be warned!
Prove that the θ scheme (I − θkD + D −)v n+1 j = (I + (1 − θ)kD + D −)v n j , j = 0, 1,. .. , N, 0 ≤ θ ≤ 1 (1) is unconditionally stable for θ ≥ 1 2. In order to find the necessary conditions for stability, we begin by making the ansatz v n j = 1 √ 2π e iωx j ˆ v n (ω), where the solution is composed of a single Fourier component. Substituting this expression into Equation 1, we obtain the foll...
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