Let G be a simple graph with vertex set V(G) {v1,v2 ,...vn} . For every vertex i v , ( ) i  v represents the degree of vertex i v . The h-th order of Randić index, h R is defined as the sum of terms 1 2 1 1 ( ), ( )... ( ) i i ih  v  v  v  over all paths of length h contained (as sub graphs) in G . In this paper , some bounds for higher Randić index and a method for computing the higher R...

aim : this study was designed to evaluate the frequency of antibody against these viruses in individuals attending the endoscopy ward of taleghani hospital tehran, iran. background : blood-borne viruses such as hepatitis b and hepatitis c virus and htlv-1 virus are among the world’s public health problems. hepatitis viruses cause liver problems and htlv-1 infection can lead to adult t-cell lymp...

background: benign paroxysmal positional vertigo (bppv) is a condition with recurrent attacks in a significant proportion of patients. the present case- control study was conducted to assess the influence of serum vitamin d normalization on recurrent attacks of vitamin d deficient patients. methods: diagnosis of bppv was made based on history and clinical examination and exclusion of other cond...

A graph G = (V,E) with p vertices and q edges is said to be a total mean cordial graph if there exists a function f : V (G) → {0, 1, 2} such that f(xy) = [(f(x)+f(y))/2] where x, y ∈ V (G), xy ∈ E(G), and the total number of 0, 1 and 2 are balanced. That is |evf (i) − evf (j)| ≤ 1, i, j ∈ {0, 1, 2} where evf (x) denotes the total number of vertices and edges labeled with x (x = 0, 1, 2). In thi...

1 Useful Linear Algebra Let v = (v1, v2, . . . , vn) be a non-zero n-dimensional row vector and P an n× n matrix. • We say v is an eigenvector of P with corresponding eigenvalue λ iff vP = λv. • The L1-norm of v (denoted ‖v‖1) is ∑n i=1 vi. • The L2-norm of v (denoted ‖v‖2) is √∑n i=1 v 2 i . • The inner product of two vectors v and w (denoted v ·w) is ∑n i=1 viwi. • We say vectors v,v, . . .v ...

Therefore to find P (S = stuck |V = static, T = cold) we need to evaluate the distribution in the denominator, P (S, V = static, T = cold). Using the sum rule, we have: P (S, V = static, T = cold) = ∑ D ∑ C ∑ J ∑ I P (D,C, S, J, I, V = static, T = cold) (4) Plugging (1) into (4), we get: P (S, V = static, T = cold) = ∑ D ∑ C ∑ J ∑ I P (D)P (C|D)P (S)P (J |D)P (I|C)P (V = static|C, S, J)P (T = c...