نتایج جستجو برای: strongly jordan zero

تعداد نتایج: 375216  

Let $R$ be a 2-torsion free ring and $U$ be a square closed Lie ideal of $R$. Suppose that $alpha, beta$ are automorphisms of $R$. An additive mapping $delta: R longrightarrow R$ is said to be a Jordan left $(alpha,beta)$-derivation of $R$ if $delta(x^2)=alpha(x)delta(x)+beta(x)delta(x)$ holds for all $xin R$. In this paper it is established that if $R$ admits an additive mapping $G : Rlongrigh...

Journal: :CoRR 2004
Bernard Parisse Morgane Vaughan

X iv :c s/ 04 12 00 5v 1 [ cs .S C ] 2 D ec 2 00 4 Jordan Normal and Rational Normal Form Algorithms Bernard Parisse, Morgane Vaughan Institut Fourier CNRS-UMR 5582 100 rue des Maths Université de Grenoble I 38402 St Martin d'Hères Cédex Résumé In this paper, we present a determinist Jordan normal form algorithms based on the Fadeev formula : (λ · I − A) ·B(λ) = P (λ) · I where B(λ) is (λ · I −...

2010
LEANDRO CAGLIERO

Let g be a finite dimensional Lie algebra over a field k of characteristic zero. An element x of g is said to have an abstract Jordan-Chevalley decomposition if there exist unique s, n ∈ g such that x = s + n, [s, n] = 0 and given any finite dimensional representation π : g → gl(V ) the Jordan-Chevalley decomposition of π(x) in gl(V ) is π(x) = π(s) + π(n). In this paper we prove that x ∈ g has...

Journal: :Annals of Mathematics 2021

In this paper we provide a proof of the Carleson $\varepsilon^2$-conjecture. This result yields characterization (up to exceptional sets zero length) tangent points Jordan curve in terms finiteness associated $\varepsilon^2$-square function.

This article examines annihilators in the skew polynomial ring $R[x;alpha,delta]$. A ring is strongly right $AB$ if everynon-zero right annihilator is bounded. In this paper, we introduce and investigate a particular class of McCoy rings which satisfy Property ($A$) and the conditions asked by P.P. Nielsen. We assume that $R$ is an ($alpha$,$delta$)-compatible ring, and prove that, if $R$ is ni...

2003
YUAN WU Vern I. Paulsen

A bounded linear operator T on a complex Hilbert space H is irreducible if it has no reducing subspace other than the trivial ones (0) and H; it is strongly irreducible if every operator similar to T is irreducible. Equivalently, T is irreducible (resp. strongly irreducible) if the only projections (resp. idempotent operators) commuting with T are 0 and I. Since (strongly) irreducible operators...

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