نتایج جستجو برای: owa operators
تعداد نتایج: 99141 فیلتر نتایج به سال:
Social media are an essential source of meaningful data that can be used in different tasks such as sentiment analysis and emotion recognition. Mostly, these solved with deep learning methods. Due to the fuzzy nature textual data, we consider using classification methods based on rough sets.Specifically, develop approach for SemEval-2018 detection task, nearest neighbour (FRNN) classifier enhan...
We investigate the aggregation phase of multicriteria decision making procedures. Characterizations of some classes of nonconventional aggregation operators are established. The first class consists of the ordered weighted averaging operators (OWA) introduced by Yager. The second class corresponds to the weighted maximum defined by Dubois and Prade. The dual class (weighted minimum) and some or...
Two linguistic-based voting systems have been introduced in recent years, namely: Majority Judgement (Balinski and Laraki, 2007) and Range Voting (Smith, 2000). The keys for them are aggregation procedures based on the median and the arithmetic mean of the grades assessed to the alternatives, respectively. In this paper a comprehensive framework based on centered OWA operators (Yager, 2007) and...
A class of extended aggregation operators, called impact functions, is proposed and their basic properties are examined. Some important classes of functions like generalized ordered weighted averaging (OWA) and ordered weighted maximum (OWMax) operators are considered. The general idea is illustrated by the Producer Assessment Problem which includes the scientometric problem of rating scientist...
This work studies the L-fuzzy context sequences when L is a complete lattice extending the results obtained in previous works with L = [0, 1]. To do this, we will use n-ary OWA operators on complete lattices. With the aid of these operators, we will study the different contexts values of the sequence using some new relations. As a particular case, we have the study when L = J ([0, 1]). Finally,...
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