نتایج جستجو برای: paulings e s b rules
تعداد نتایج: 2444819 فیلتر نتایج به سال:
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Using the general form of ΣQ and ΛQ (Q = b or c) currents, ΣQΛQ transition magnetic moments are calculated in framework of the light cone QCD sum rules method. In this approach nonperturbative effects are described by the photon wave functions and only two–particle photon wave functions are taken into account. Our predictions on transition magnetic moments are μΣcΛc = −(1.5±0.4)μN and μΣbΛb = −...
For simplicity, we adopt the following rules: n denotes an element of N, V denotes a subset of the carrier of En T , s, s1, s2, t, t1, t2 denote points of E n T , C denotes a simple closed curve, P denotes a subset of the carrier of E T , and a, p, p1, p2, q, q1, q2 denote points of E 2 T . Next we state several propositions: (1) For all real numbers a, b holds (a − b) = (b − a). (2) Let S, T b...
The light cone QCD sum rules method is used to calculate the transition form factor for the radiative φ → f0γ decay, assuming that quark content of the f0 meson is pure s̄s state. The branching ratio is estimated to be B(φ → f0γ) = 3.5 × (1 ± 0.3) × 10. A comparison of our prediction on branching ratio with the theoretical results and experimental data existing in literature is presented. PACS n...
1. Proof. (a) It is known that all finite dimensional distributions of X(t) are multivariate normal with E(X(s)) = 0 and E(X(s)X(t)) = min{s, t}. It is easy to see that B(t) ∼ N(0, t), B(t′)−B(t) = X(s+ t′)−X(s+ t) ∼ N(0, t′− t) (t′ > t) and B(t0), B(t1) − B(t0), ..., B(tn) − B(tn−1) are independent. Hence all finite dimensional distributions of B(t) are multivariate normal with E(B(t)) = 0. Su...
Two set systems E , F on an underlying set V will be said to have Property S if there exists a subset σ of V , such that σ ∩ e 6= ∅, for all e ∈ E and f 6⊆ σ, for all f ∈ F (see [8], [9]]). We give rules for deciding Property S, which generalizes the very successful Davis-Putnam rules for deciding satisfiability in propositional logic.
m e a n i n g t h a t e a c h d i s t r i b u t e d s u b p r o b l e m i s s o l v a b l e i n d e p e n d e n t l y a n d t h e s o l u t i o n o f o n e d o e s n o t a f f e c t t h e s o l u t i o n o f o t h e r s . W e w i l l c o n s i d e r t h e e f f e c t s o f r e l a x i n g t h i s a s s u m p t i o n i n S e c t i o n 3 . 3 . 4 . 2 . T h e s o l u t i o n f o u n d h i e r a r c...
Theorem 7.1 (4.2) Let T be a set of transformation rules. The transformation testing problem is NP-complete for T with star-free rules, where does not appear on the rhs of atomic rules. Remark: Note that the reenement rule r 0 of Section 2 is not star-free, and thus the above theorem does not apply. Nevertheless, the transformation testing for it is in NP-TIME. (Each application of the rule r s...
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