نتایج جستجو برای: solvable l

تعداد نتایج: 628574  

2006
Zhongwei Shen ZHONGWEI SHEN

Abstract. Using Maz’ya type integral identities with power weights, we obtain new boundary estimates for biharmonic functions on Lipschitz and convex domains in R. For n ≥ 8, combined with a result in [S2], these estimates lead to the solvability of the L Dirichlet problem for the biharmonic equation on Lipschitz domains for a new range of p. In the case of convex domains, the estimates allow u...

1999
Augustin Baziramwabo Pierre McKenzie Denis Thérien

Th erien and Wilke characterized the Until hierarchy of linear temporal logic in terms of aperiodic monoids. Here, a temporal operator able to count modulo q is introduced. Temporal logic augmented with such operators is found decidable as it is shown to express precisely the solvable regular languages. Natural hierarchies are shown to arise when modular and conventional operators are interleav...

2004
Monika Lynker

It is shown how the arithmetic structure of algebraic curves encoded in the HasseWeil L-function can be related to affine Kac-Moody algebras. This result is useful in relating the arithmetic geometry of Calabi-Yau varieties to the underlying exactly solvable theory. In the case of the genus three Fermat curve we identify the Hasse-Weil L-function with the Mellin transform of the twist of a numb...

2004
Badis Ydri

Noncommutative U (1) gauge theory in 4−dimensions is shown to be equivalent in some scaling limit to an ordinary non-linear sigma model in 2−dimensions. The model in this regime is solvable and the corresponding exact beta function is found. We also show that classical U (n) gauge theory on R d−2 ×R 2 θ can be approximated by a sequence of ordinary (d − 2)−dimensional Georgi-Glashow models with...

Journal: :Journal de Theorie des Nombres de Bordeaux 2022

The first aim of this note is to fill a gap in the literature by giving proof following refinement Shafarevich's theorem on solvable Galois groups: Given global field $k$, finite set $\mathcal{S}$ primes and group $G$, there extension $k$ $G$ which all are totally split. To that end, we prove that, given every split embedding problem $G \rightarrow {\rm{Gal}}(L/k)$ over with nilpotent kernel ha...

Journal: :Discrete Applied Mathematics 1980

1994
Ilya Kapovich

The main result of this paper states that for any group G with an automatic structure L with unique representatives one can construct a uniform partial algorithm which detects L-rational subgroups and gives their preimages in L. This provides a practical, not just theoretical, procedure for solving the occurrence problem for such subgroups. 1. Generalized word problem and rational structures on...

2004
Vladimir P. BURSKII

smooth coefficients aα(x), L+ be a formally adjoint differential operation. Let L0, L0 be minimal operators (i.e., for example, D(L0) is the clozure of C∞ 0 (Ω) in the norm of the graph ‖u‖L = ‖u‖L2(Ω)+‖Lu‖L2(Ω)), and L, L+ be maximal expansions of L,L+ in the space L2(Ω) respectively (i.e. L = (L0 ) ∗, L+ = (L0)∗), L̃ = L|D(L̃) where D(L̃) is the clozure of C∞(Ω̄) in the norm of the graph ‖u‖L and...

Journal: :Discrete Mathematics 2001
Wenwen Tong Huiling Li

Let G be a solvable block transitive automorphism group of a 2− (v; 5; 1) design and suppose that G is not 0ag transitive. We will prove that (1) if G is point imprimitive, then v = 21, and G6 Z21 : Z6; (2) if G is point primitive, then G6A L(1; v) and v = p, where p is a prime number with p ≡ 21 (mod 40), and a an odd integer. c © 2002 Elsevier Science B.V. All rights reserved.

2006
K. DEKIMPE

We prove that N( f )= |L( f )| for any continuous map f of a given infranilmanifold with Abelian holonomy group of odd order. This theorem is the analogue of a theorem of Anosov for continuous maps on nilmanifolds. We will also show that although their fundamental groups are solvable, the infranilmanifolds we consider are in general not solvmanifolds, and hence they cannot be treated using the ...

نمودار تعداد نتایج جستجو در هر سال

با کلیک روی نمودار نتایج را به سال انتشار فیلتر کنید