(*)' Fn = ox. In [1], Cohn solved (*) for c = 1, 2. In [9], we found all solutions of O ) such that <? is prime and either o = 3 (mod 4) or c < 10,000. Harborth & Kemnitz [4] have asked for solutions of (&) for composite values of o. Clearly, it suffices to consider only squarefree values of c. If c < 1000, then c has at most three distinct odd prime factors. Therefore c = kp where p is prime a...