0 = fx 0 a; y 0 bg I 1 = (ffx x 0 ; z z 0 g 0 =: 1 g; ;) 1 = fx a; z z 0 g Hence, the original constraint can be simplied to C 1 = f:s(a; z 0);r(a;z 0)g, which is easily refuted by looking up s(a,c 50) and disproving r(a,c 50). It should be quite obvious that the advantage of the additional exibility provided by our mechanism heavily depends on a good procedure for deciding whether to take an e...
