A finite image I is a function assigning colors to a finite, rectangular array of discrete pixels. Thus, the information directly encoded by I is purely locational. Such locational information is of little visual use in itself: perception of visual structure requires extraction of relational image information. A very elementary form of relational information about I is provided by its dipole hi...

Glucocorticoid hypertension was induced by oral administration of dexamethasone (DX) in male Wistar rats. The mechanism of hypertension was studied by observing the changes in plasma renin activity, urinary excretion of prostaglandin E2 (PGE2), and the pressor response to norepinephrine. Following administration of DX (0.1 mg/day), the blood pressure began to rise within 3 days and reached a pl...

In this paper‎, ‎using a generalized Dunkl translation operator‎, ‎we obtain a generalization of Titchmarsh's Theorem for the Dunkl transform for functions satisfying the$(psi,p)$-Lipschitz Dunkl condition in the space $mathrm{L}_{p,alpha}=mathrm{L}^{p}(mathbb{R},|x|^{2alpha+1}dx)$‎, ‎where $alpha>-frac{1}{2}$.  

Using a generalized spherical mean operator, we obtain a generalization of Titchmarsh's theorem for the Dunkl transform for functions satisfying the ('; p)-Dunkl Lipschitz condition in the space Lp(Rd;wl(x)dx), 1 < p 6 2, where wl is a weight function invariant under the action of an associated re ection group.

OBJECTIVE Oncotype DX, a 21-gene assay, was clinically validated as a predictor of 10-year recurrence-free survival and treatment response in patients with early-stage estrogen-receptor-positive, lymph-node negative breast cancer (ER+ LN- ESBC). This study determined "real-life" alteration in treatment decision and economic implications of Oncotype DX use in women with ER+ LN- ESBC. METHODS C...

We evaluate the integral ∞ 0 · · · ∞ 0 1≤i<j≤n (x j − x i) 2 e −x1 dx 1 · · · e −xn dx n using orthogonal polynomials and techniques from linear algebra.

Let {Lt ; (x, t) ∈ R1 ×R1 +} denote the local time of Brownian motion and αt := ∫ ∞ −∞ (Lt ) 2 dx. Let η = N(0, 1) be independent of αt. For each fixed t ∫∞ −∞(L x+h t − Lt )2 dx− 4ht h3/2 L → ( 64 3 )1/2 √ αt η, as h → 0. Equivalently ∫∞ −∞(L x+1 t − Lt )2 dx− 4t t3/4 L → ( 64 3 )1/2 √ α1 η, as t → ∞.