A p a s s i v e h a e m a g g l u t i n a t i o n tes t ( P H A ) for h u m a n n e u r o c y s t i c e r c o s i s w a s s t a n d a r d i z e d a n d e v a l u a t e d for the de tec t i on of spec i f i c a n t i b o d i e s to C y s t i c e r c u s c e l l u losae i n c e r e b r o s p i n a l f l u id ( C S F ) . F o r the a s s a y , f o r m a l d e h y d e t r e a t e d g r o u p O R h h...

T h e m o l e c u l a r s t r u c t u r e o f t h e l e t h y l 3 m e t h y l l a l u m i n a i n d a n e d i m e r h a s b e e n d e t e r m i n e d f r o m s i n g l e c r y s t a l X r a y d a t a c o l l e c t e d b y c o u n t e r m e t h o d s . T h e c o m p o u n d c r y s t a l l i z e s i n t h e m o n o c l i n i c s p a c e g r o u p C | h P 2 i / c w i t h a = 1 4 . 6 2 1 ( 2 ) , b...

and Applied Analysis 3 Moreover, using the condition (iii), we obtain z (t) ≤ h (t) h −1 (τ 0 ) ( 󵄩󵄩󵄩󵄩y0 − x0 󵄩󵄩󵄩󵄩 + 󵄨󵄨󵄨󵄨η 󵄨󵄨󵄨󵄨) . (12) Then from (12), we get 󵄩󵄩󵄩󵄩x (t, τ0, y0) − x (t − η, t0, x0) 󵄩󵄩󵄩󵄩 ≤ [ 󵄩󵄩󵄩󵄩y0 − x0 󵄩󵄩󵄩󵄩 + 󵄨󵄨󵄨󵄨τ0 − t0 󵄨󵄨󵄨󵄨] h (t) h −1 (τ 0 ) . (13) So by Definition 1 with c = 1, the solution x(t, τ 0 , y 0 ) of (2) is ITDhS with respect to the solution x(t − η, t 0 , x 0 ). T...

4 B r o m o x a n t h o t o x i n r e a c t s w i t h c y a n o a c e t a m i d e t o f o r m 4 b r o m o 5 , 6 d i h y d r o x a n t h o t o x i n , w h i c h o n h y d r o l y s i s w i t h c o l d h y d r o c h l o r i c a c i d l e a d s t o t h e f o r m a t i o n o f c y a n o a c e t i c a c i d d e r i v a t i v e , b u t h y d r o l y s i s b y b o i l e d h y d r o c h l o r i c a c i...

We p r e s e n t and a n a l y s e e x p e r i m e n t a l r e s u l t s i n t h e f i r s t e x t e n s i v e use o f a theo rem p r o v e r based o n R e s o l u t i o n b y U n i f i c a t i o n and E q u a l i t y . I m p l i c i t use i s made o f e q u a l i t y ax ioms b y t h e I n f e r e n c e r u l e s RUE and NRF to a c h i e v e i n c i s i v e r e f u t a t i o n s f o r E u n s a...

o f t h e a H a s H + a n d l e a d s t o a n i n t e r m e d i a t e i n w h i c h t h e s u b s t r a t e a C c a r r i e s a n e g a t i v e c h a r g e . I n t h e " h y d r i d e m e c h a n i s m " a H i s e x p u l s e d f r o m a C H o C o m b i n a t i o n s o f t h e s e m e c h a n i s m s a l s o h a s b e e n p r o p o s e d ( 1 ) . W e h a v e a d d r e s s e d t h e q u e s t i o...

the a f f i x e s i n a l a n g u a g u e are a masive w e b o f morfolexical elements formed b y t w o bases ; t h e root and t h e bound . t h e combination o f these t w o link the meaning o f a w o rd with a concept . t h e a i m o f t h e present paper i s t o study t h e similitud and dissimilitude i n t h e funtion o f these suffixes i n b o t h spanish a n d persian languages . we will ...

J. Knoll D e p a r t m e n t of P h a r m a c o l o g y , Semmelweis U n i v e r s i t y of M e d i a n e , Budapest, H u n g a r y K.D. Kohn L a b o r a t o r y of B i o c h e m i c a l P h a r m a c o l o g y , N a t i o n a l I n s t i t u t e of A r t h r i t i s , M e t a b o l i s m a n d D i g e s t i v e Diseases, N a t i o n a l I n s t i t u t e s of H e a l t h , Bethesda, M a r y l ...

In this paper, we give an another proof of Theorem 3 in [4]. Theorem 3 in [4] is the following theorem. Theorem 1. Let ζ(s) be the Riemann zeta function and let ζ * (s) = π −s/2 Γ(s/2)ζ(s). For each y ≥ 1 the constant term of the Eisenstein series a 0 (y, s) := ζ * (2s)y s + ζ * (2 − 2s)y 1−s (1) is a meromorphic function that satisfies the modified Riemann hypothesis. More precisely , there is...

A mode l based compute r v i s i o n sys tem has been d e v e l o p e d w h i c h can d e t e r m i n e t h e p o s i t i o n and o r i e n t a t i o n o f s e v e r a l p a r t s i n t h e same s c e n e . The p a r t s can b e o f t h e same t y p e o r o f d i f f e r e n t t y p e s . F u r t h e r m o r e , t h e sys tem can work w i t h v i s u a l l y n o i s y scenes and some o c c l u ...