نتایج جستجو برای: classical p adic groups

تعداد نتایج: 1942112  

2000
CHRIS JANTZEN

In this paper, we continue our study of non-supercuspidal discrete series for the classical groups Sp(2n, F ), SO(2n+ 1, F ), where F is p-adic.

2001
JU-LEE KIM

In the previous part of this paper, we constructed a large family of Hecke algebras on some classical groups G de¢ned over p-adic ¢elds in order to understand their admissible representations. EachHecke algebra is associated to a pair …JS; rS†of an open compact subgroup JS and its irreducible representation rSwhich is constructed fromgiven dataS ˆ …G;P0 0; R†. Here, G is a semisimple element in...

2006
Shaun Stevens

Let G be a unitary, symplectic or special orthogonal group over a locally compact nonarchimedean local field of odd residual characteristic. We construct many new supercuspidal representations of G, and Bushnell-Kutzko types for these representations. Moreover, we prove that every irreducible supercuspidal representation of G arises from our constructions.

Journal: :Journal of Algebra 2013

Journal: :Proceedings of the American Mathematical Society 2021

Let G n G_n denote either the group S p left-parenthesis 2 n comma upper F right-pa...

2011
Amir Džambić Gareth A. Jones

Herrlich showed that a Mumford curve of genus g > 1 over the p-adic complex field Cp has at most 48(g− 1), 24(g− 1), 30(g− 1) or 12(g− 1) automorphisms as p = 2, 3, 5 or p > 5. The Mumford curves attaining these bounds are uniformised by normal subgroups of finite index in certain p-adic triangle groups ∆p for p ≤ 5, or in a p-adic quadrangle group p for p > 5. The finite groups attaining these...

‎We first give bounds for domains where the unitarizabile subquotients can show up in the parabolically induced representations of classical $p$-adic groups‎. ‎Roughly‎, ‎they can show up only if the‎ ‎central character of the inducing irreducible cuspidal representation is dominated by the‎ ‎square root of the modular character of the minimal parabolic subgroup‎. ‎For unitarizable subquotients...

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