نتایج جستجو برای: mixed roman dominating function

تعداد نتایج: 1433079  

Journal: :Discussiones Mathematicae Graph Theory 2018

Journal: :Discrete Mathematics & Theoretical Computer Science 2021

A mixed dominating set is a collection of vertices and edges that dominates all graph. We study the complexity exact parameterized algorithms for \textsc{Mixed Dominating Set}, resolving some open questions. In particular, we settle problem's by treewidth pathwidth giving an algorithm running in time $O^*(5^{tw})$ (improving current best $O^*(6^{tw})$), as well lower bound showing our cannot be...

Journal: :Symmetry 2021

This paper is devoted to the study of quadruple Roman domination in trees, and it a contribution Special Issue “Theoretical computer science discrete mathematics” Symmetry. For any positive integer k, [k]-Roman dominating function ([k]-RDF) simple graph G from vertex set V {0,1,2,…,k+1} if for u?V with f(u)<k, ?x?N(u)?{u}f(x)?|{x?N(u):f(x)?1}|+k, where N(u) open neighborhood u. The weight [k...

Journal: :Australasian J. Combinatorics 2011
P. Roushini Leely Pushpam T. N. M. Malini Mai

Let G = (V,E) be a graph and let f be a function f : E → {0, 1, 2}. An edge x with f(x) = 0 is said to be undefended with respect to f if it is not incident to an edge with positive weight. The function f is a weak edge Roman dominating function (WERDF) if each edge x with f(x) = 0 is incident to an edge y with f(y) > 0 such that the function f ′ : E → {0, 1, 2}, defined by f ′(x) = 1, f ′(y) =...

2012
Yen Hung Chen

Given a graph G = (V,E), a mixed dominating set MD of G is defined to be a subset of V ∪ E such that every element in {(V ∪E)\MD} is either adjacent or incident to an element of MD. The mixed dominating set problem is to find a mixed dominating set with minimum cardinality. This problem is NP-hard. In this paper, we prove that this problem is MAX SNP-hard.

Journal: :Ars Mathematica Contemporanea 2021

Let G be a graph with no isolated vertex and f : V ( ) → {0, 1, 2} function. i = { x ∈ } for every . We say that is total Roman dominating function on if in 0 adjacent to at least one 2 the subgraph induced by 1 ∪ has vertex. The weight of ω ∑ v minimum among all functions domination number , denoted γ t R It known general problem computing NP-hard. In this paper, we show H nontrivial graph, th...

2002
Aris Pagourtzis Paolo Penna Konrad Schlude Kathleen Steinhöfel David Scot Taylor Peter Widmayer

Dominating sets in their many variations model a wealth of optimization problems like facility location or distributed le sharing. For instance, when a request can occur at any node in a graph and requires a server at that node, a minimumdominating set represents a minimum set of servers that serve an arbitrary single request by moving a server along at most one edge. This paper studies dominat...

Journal: :Discussiones Mathematicae Graph Theory 2011
T. N. M. Malini Mai P. Roushini Leely Pushpam

Let G = (V,E) be a graph and f be a function f : V → {0, 1, 2}. A vertex u with f(u) = 0 is said to be undefended with respect to f , if it is not adjacent to a vertex with positive weight. The function f is a weak Roman dominating function (WRDF) if each vertex u with f(u) = 0 is adjacent to a vertex v with f(v) > 0 such that the function f ′ : V → {0, 1, 2} defined by f ′ (u) = 1, f ′ (v) = f...

2013
Mathieu Chapelle Manfred Cochefert Jean-François Couturier Dieter Kratsch Mathieu Liedloff Anthony Perez

We investigate a domination-like problem from the exact exponential algorithms viewpoint. The classical Dominating Set problem ranges among one of the most famous and studied NP -complete covering problems [6]. In particular, the trivial enumeration algorithm of runtime O∗(2n) 4 has been improved to O∗(1.4864n) in polynomial space, and O∗(1.4689n) with exponential space [9]. Many variants of th...

Journal: :Journal of Physics: Conference Series 2021

Definition of dominating function on a fractional graph G has been introduced. Fractional parameters such as domination number and upper defined. Domination with fuzzy Intuitionistic environment, have found by formulating Linear Programming Problem.

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